Concepts

What is the Centripetal Force?

  • We know that an object in circular motion keeps on changing its direction.
  • Due to this, the velocity of the object also changes.
  • A force called Centripetal Force acts upon the object that keeps it moving in a circular path.
  • The centripetal force is exerted from the centre of the path.
  • Without the Centripetal Force objects cannot move in circular paths, they would always travel straight.
  • For Example, The rotation of the Moon around the Earth is possible because of the centripetal force exerted by Earth.

Figure 1 Centripetal Force of Earth on Moon

Newton's Observations

  • Why does Apple fall on Earth from a tree? – Because the earth attracts it towards itself.
  • Can Apple attract the earth?  - Yes. It also attracts the earth as per Newton's third law (every action has an equal and opposite reaction). But the mass of the earth is much larger than Apple's mass thus the force applied by Apple appears negligible and Earth never moves towards it.
  • Newton thus suggested that all objects in this universe attract each other. This force of attraction is called Gravitational Force.

Figure 2 Gravitational Force of Earth

Universal Law of Gravitation by Newton

  • According to the universal law of gravitation, every object attracts every other object with a force.
  • This force is directly proportional to the product of their masses.
  • This force is inversely proportional to the square of distances between them.
  • Consider the figure given below. It depicts the force of attraction between two objects with masses m1 and m2 respectively that are ‘d’ distance apart.

  • The figure below describes how the universal law of gravitation is derived mathematically.

From the above equation we can rewrite them as the following:

If we remove the proportionality we get proportionality constant G as the following:

The above equation is the mathematical representation of Newton’s Universal Law of gravitation

Hence, G = Fr2/ mm2

SI Unit: Nm2 kg-2

Value of G = 6.673 × 10-11 Nm2 kg-2 (was found out by Henry Cavendish (1731- 1810))

  • The proportionality constant G is also known as the Universal Gravitational Constant

Why do we study the universal law of gravitation?

It explains many important phenomena of the universe –

  • Earth’s gravitational force
  • Why the moon always moves in a circular motion around the earth and the sun
  • Why all planets revolve around the sun
  • How the sun and moon can cause tides

Free Fall

  • Acceleration due to gravity – Whenever an object falls towards the Earth there is an acceleration associated with the movement of the object. This acceleration is called acceleration due to gravity.
  • Denoted by: g
  • SI Unit: m s-2
  • We know that, F= ma
  • Therefore, F = mg
  • The following figure demonstrates the mathematical derivation of ‘g'

The force (F) of gravitational attraction on a body of mass m due to earth of mass M and radius R is given by

We know from Newton’s second law of motion that the force is the product of mass and acceleration.

∴  F = ma

But the acceleration due to gravity is represented by the symbol g. Therefore, we can write

F = mg           ….. (2)

From the equation (1) and (2), we get

When the body is at a distance ‘r’ from the centre of the earth then

the Value of ‘g' may vary at different parts of the earth –

  • From the equation g = GM/ r2 it is clear that the value of ‘g' depends upon the distance of the object from the earth's centre.
  • This is because the shape of the earth is not a perfect sphere. It is rather flattened at poles and bulged out at the equator.
  • Hence, the value of ‘g' is greater at the poles and lesser at the equator. However, for our convenience, we take a constant value of ‘g' throughout.

We can find the value of acceleration due to gravity by the following –

What is Free Fall?

When an object falls towards the earth due to the earth’s gravity and no other force is acting upon it, the object is said to be in a free-fall state. Free-falling objects are not even resisted by the air.

g = 9.8 m/s2 is also called the Free-fall Acceleration.

Value of ‘g' is the same on the earth, so the equations of motion for an object with uniform motion are valid where acceleration ‘a' is replaced by ‘g', as given under:

v = u + gt

s = ut + (1/2) gt2

2 g s = v2 – u2

Consider the equations of motion given in different scenarios:

When an object at rest falls towards earth – its initial velocity is zero

v = gt

s = t + (1/2) gt2

2 g s = v2

When an object with some initial velocity (u) falls towards earth –

v = u + gt

s = ut + (1/2) gt2

2 g s = v2 – u2

When an object is thrown upwards from the earth – the gravitational force acts in opposite direction, hence g is negative

v = u - gt

s = ut - (1/2) gt2

-2 g s = v2 – u2

Difference between Universal gravitational Constant and Acceleration due to Gravity

Mass Weight 
Mass is defined as the quantity of matter in an object. The weight of an object is the force by which the gravitational pull of the earth attracts the object.
Mass is a scalar quantity Weight is a vector quantity
The mass of an object is always constant as it depends upon the inertia of the object The weight of an object can vary at different locations because of change in gravitational force of the earth
Mass can never be zero Weight can be zero at places there is no gravitational force
Denoted as: m Denoted  as W
F = mg
where m = mass of object
a = acceleration due to gravity
Similarly, W is force, so
W = mg
SI Unit: kg SI unit: N

Weight of an object on the Moon

Just like the Earth, the Moon also exerts a force upon objects. Hence, objects on the moon also have some weight. The weight will not be the same as on the earth. So, weight on the Moon can be calculated as -

Thrust and Pressure

Thrust

  • The force that acts in the perpendicular direction is called thrust.
  • It is similar to force applied to an object
  • It is a vector quantity.

 

Pressure

  • The force that acts per unit area of the object is pressure.
  • It is the thrust per unit area.
  • Pressure is denoted by ‘P'
  • P = thrust/ area = force/ area = F/A
  • SI unit: N/m2 or Pa (Pascal)

Figure 4 Pressure

Why do nails have sharp edges?

We know that pressure is inversely proportional to area. As area increases, pressure decreases and vice versa. So, nails' sharp edges make it easier for them to get into the wall because more pressure is exerted on the wall from a single point.

  • Solids - They exert pressure on the surface because of their weight.
  • Fluids (gases and liquids) - They also have weight, therefore, they exert pressure on the surface and the walls of the container in which they are put in.

Buoyancy

  • Whenever an object is immersed in a liquid, the liquid exerts a buoyant force or upthrust in the opposite direction of the gravitational force. This is also called the Force of Buoyancy.
  • It depends upon the density of the fluid.
  • Therefore an object is able to float in water when the gravitational force is less than the buoyant force.
  • Similarly, an object sinks into the water when the gravitational force is larger than the buoyant force.

Figure 5 Buoyancy

Why does an object sink or float on water?

  • An object can sink or float on water based on its density with respect to water. The density is defined as mass per unit volume.
  • Objects having a density less than water float in it. For Example, Cork flows in water because its density is lower than that of water.
  • Objects that have a density higher than water sink in it. For Example, Iron nails sink in water because the density of iron is more than water's density.
  • Thus, we can conclude that buoyancy depends upon:
    • The density of the liquid
    • The volume of the object (as the volume of object increases, its density decreases and vice-versa)

Archimedes Principle

According to the Archimedes principle, whenever an object is immersed in a liquid (fully or partially), the liquid exerts an upward force upon the object. The amount of that force is equivalent to the weight of the liquid displaced by the object.

This means that if the weight of an object is greater than the amount of liquid it displaces, the object will sink into the liquid. However, if the weight of an object is less than the amount of water it displaces, the object will sink.

  • Submarines have a tank called Buoyancy Tank. Whenever the submarine needs to be taken inside water the tank is filled which thus increases the weight of the submarine. Similarly, when the submarine is to appear above water the tank is emptied and the weight of the submarine becomes lighter and it rises above the water.
  • Ships are heavier than water but their unique shape gives them a large volume. Their volume is larger than their weight and hence the water displaced by a ship provides it with the right upthrust so that it can float on water.

Applications of Archimedes Principle

  • In evaluating relative density
  • In designing ships and submarines
  • In making lactometers and hydrometers

What is relative density?

When density can be expressed in comparison with water's density it is called Relative Density. It has no unit because it is a ratio of two similar quantities.

Why is water chosen as a reference?

Water is present everywhere on earth so it becomes easier to evaluate the density of a substance in relation to water.

How relative density can be used as a measure to determine if an object will sink or float in water?

Relative Density of an object  Float / Sink 
Greater than 1 Sink in water
Less than 1 Float in water

 

Questions & Answers

Q1. How does the force of gravitation between two objects change when the distance between them is reduced to half?
Ans.         The force of gravitation becomes 4 times more.
Q2. Gravitational force acts on all objects in proportion to their masses. Why then, a heavy object does not fall faster than a light object?
Ans. The heavy object when falls, the acceleration due to gravity ‘g’ is acting which is independent of the mass of the body.
        
        Gravitation force is 
        ∴ F and g are different.
Q3. What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface?
        [Mass of the earth is 6 x 1024 kg and radius of the earth is 6.4 x 106 m].
Ans. The magnitude of the gravitational force between earth and an object is given by the formula.
        
Q4. The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is greater or smaller or the same as the force with which the moon attracts the earth? Why?
Ans. The value of F is same for earth and the moon. Both bodies will exert the same amount of force on each other.
        As per universal law of gravitation, every body attracts the other body with some force and this force is same for both the bodies called gravitational force.
Q5. If the moon attracts the earth, why does the earth not move towards; the moon?
Ans. According to the universal, law of gravitation both moon and earth attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of distance between them.
        The force of attraction of moon’ on the earth is present, but the earth does not appear to move towards the moon as the mass of the earth is large and the distance between the moon and earth is so large, even if the earth is attracted/moves towards the ,moon it is negligible, cannot be seem.
Q6. What: happens to the force between two objects, if
        (i) the mass of one object is doubled?
        (ii) the distance between the objects is doubled and tripled?
        (iii) the masses of both objects are doubled?
Ans. (i) If the mass of one object is doubled, the force between two objects will be doubled (increases)
        (ii) If the distance been the objects is doubled the force between two objects will be one-fourth and if the distance will be tripled, the force will be one-ninth (1/9).
        (iii) If the masses of both objects are doubled the force will be 4 times.
                
Q7. What is the importance of universal law of gravitation?
Ans. The universal law of gravitation explains several phenomena:
        (i) it explains about the force that binds the earth,
        (ii) the motion of the moon around the earth,
        (iii) the motion of planets around the sun, and
        (iv) the tides due to the moon and the sun.
Q8. What is the acceleration-of free fall?
Ans. The acceleration of free fall is; when the Body falls due to earth’s gravitational pull, its velocity changes and is said to be accelerated due to .the earth’s gravity and it falls freely called as free fall. This acceleration is calculated to be 9.8 m/s2.
Q9. What do we call the gravitational force between the earth and an object?
Ans. The gravitational force between the earth and an object is called force due to gravity.
Q10. Amit buys few grams of gold at the poles per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not, why?
        [Hints: The value of g is greater at the poles than at the equator.]
Ans. Weight of the body is given by the formula
                W = mg
        It depends ors the value of ‘g’ i.e., acceleration due to gravity.
        The weight of gold at poles = Wp = m × g (poles)
        Value of g at poles is more than the value of g at equator.
        The weight of gold at equator = We = m × g (equator)
                ∴ Wp > We.
        The weight at pole of the same gold is found to be more as compared to the weight at the equator.
Q11. Why will a sheet of paper fall slower than one that is crumpled into a ball?
Ans. A sheet of paper has larger surface area and while falling down it has to overcome the force exerted by air/wind. current, called as air resistance.
        The crumpled paper has smaller surface area and it has to overcome very less amount of air current.
Q12. Gravitational force on the surface of the moon is only 1/6 as strong as gravitational force on the earth. What is the weight in Newtons of a 10 kg object on the moon and on the earth?
Ans. Mass of the object = 10 kg
        Weight of the object on earth = W = m × g
        ∴ W = 10 × 9.8
                W = 98 N
        Weight of the object on moon = th the weight on the earth.
        As the gravitational force on the surface of the moon is only th as strong as gravitational force on the surface of the earth.
        ∴ Weight of the object on moon 
        Weight on earth = 98 N
        Weight on moon = 16.3 N
Q13. A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate
        (i) the maximum height to which it rises,
        (ii) the total time it takes to return to the surface of the earth.
Ans. (i) Initial velocity = 49 m/s
                Final velocity = 0 m/s
                a = g = –9.8 m/s2
                Height = Distance = s = ?
                ∴ v2 – u2 = 2gs
                02 – (49)2 = 2 (–9.8) × s
                
        (ii) Time take t = ?
                v = u + gt
                ∴ 0 = 49 + (–9.8) × t
                
                Total time taken to return the surface of the earth by the ball is 5 s + 5 s = 10 s.
Q14. A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground?
Ans. Data u = 0 m/s
                v = ?
                h = s = 19.6 m
                g = 9.8 m/s2 (falling down)
                v2 – u2 = 2gs
                v2 – (0)2 = 2 x 9.8 x 19.6
                v = 19.6 m/s
         The final velocity just before touching the ground is 19.6 m/s.
Q15. A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
Ans. u = 40 m/s
                g = –10 m/s2 (going against gravity)
                h = s = ?
                v = 0
                v2 – u2 = 2gs
                (0)2 – (40)2 = 2 (–10) x s
                
         Net displacement of the stone = 0 (As the stone falls, back to the same point.)
         Total distance covered by stone = 80 m + 80 m
                                                (up)                (down)
                = 160 m
Q16. Calculate the force of gravitation between the earth and the Sun, given that the mass of the earth = 6 x 1024 kg and of the Sun = 2 x 1030 kg. The average distance between the two is 1.5 x 1011m.
Ans. Me = 6 x 1024 kg G = 6.67 x 10–11 Nm2/kg2
                Ms = 2 x 1030 kg
                d = 1.5 x 1011 m
                
Q17. A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vetically upwards from the ground with a velocity of 25 m/s. Calculate when and where the two stones will meet.
Ans. h = 100 m
                        time t = ? g = 10 m/s2
                Height covered by the falling stone = s1
                
                The distance covered by the stone thrown upward = s2
                      g = –10 m/s
                      u = 25 m/s
                
                Total height given = 100 m
                ∴ s1 + s2 = 100m
                5t2 + (25t – 5t2) = 100 m
                ∴ 25t = 100 m
                
                Putting the value of (3) in equation (1), we get
                      ∴ s1 = 5t2
                      = 5 × (4)2 = 80 m
                ∴ The two stones will meet after 4 seconds when the falling stone has covered a distance of 80 m.
Q18. A ball thrown up vertically returns to the thrower after 6 s. Find
        (a) the velocity with which it was thrown up,
        (b) the maximum height it reaches, and
        (c) its position after 4 s.
Ans. u = ?
        v = 0
        g = –9.8 m/s2 (thrown upward)
        Total time = 6 s (to go up and down)
        ∴ Time for upward journey 
        (a) v = u + gt
             0 = u = (–9.8) × 3
             u = 29.4 m/s
        (b) Maximum height h = s = ?
             
        (c) Position after 4 s
             t = 4s
             
        ∴ Position after 4 s = 39.2 m from the top.

Mock Test